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6x^2+12x+36=94
We move all terms to the left:
6x^2+12x+36-(94)=0
We add all the numbers together, and all the variables
6x^2+12x-58=0
a = 6; b = 12; c = -58;
Δ = b2-4ac
Δ = 122-4·6·(-58)
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-16\sqrt{6}}{2*6}=\frac{-12-16\sqrt{6}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+16\sqrt{6}}{2*6}=\frac{-12+16\sqrt{6}}{12} $
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